Chemistry, asked by Sykla, 9 months ago

Calculate the mass in gram of Na+ in 25g of Na2SO4

Answers

Answered by vivekanandamsc19
4

Answer:

according to mole concept. i think it is helpfull to you and please make it as brilliest answer

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Answered by niteshrajputs995
0

Answer:

The mass in gram of Na+ in 25g of Na₂SO4₂₄ : is 8.096 g ≅ 8.1 g

Explanation:

The molar mass of Na2SO4 is 142 g/mol, which means that 1 mole of Na2SO4 contains 2 moles of Na+ ions.

To find the mass of Na+ ions in 25 g of Na2SO4, we need to first calculate the number of moles of Na2SO4 present in 25 g.

Number of moles of Na2SO4 = (Mass of Na2SO4) / (Molar mass of Na2SO4)

Number of moles of Na2SO4 = 25 g / 142 g/mol

Number of moles of Na2SO4 = 0.176 moles

Since 1 mole of Na2SO4 contains 2 moles of Na+ ions, the total number of moles of Na+ ions present in 0.176 moles of Na2SO4 is:

Number of moles of Na+ ions = 2 x (Number of moles of Na2SO4)

Number of moles of Na+ ions = 2 x 0.176

Number of moles of Na+ ions = 0.352 moles

The mass of Na+ ions present in 25 g of Na2SO4 is given by:

Mass of Na+ ions = (Number of moles of Na+ ions) x (Molar mass of Na+ ions)

Mass of Na+ ions = 0.352 moles x 23 g/mol

Mass of Na+ ions = 8.096 g

Therefore, the mass of Na+ ions present in 25 g of Na2SO4 is approximately 8.1 grams.

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