Question

calculate the mass in grams of a sample of S containing 2.01×10^24 atoms​

Answer 1

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Given :- }}}}$

• A sample of Sulphur has 2.01 × 10²⁴ atoms .

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ To Find :- }}}}$

• The mass in grams of the sample .

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Solution :- }}}}$

Given that A sample of Sulphur has 2.01 × 10²⁴ atoms . And we need to find the mass of the sample . We know that the molecular mass of Sulphur is , 32 g . Therefore ,

$\sf\longrightarrow Mass \ of \ Sulphur \ = \ 32 g$

Now we know that , we can find the number of moles as ,

$\sf\longrightarrow n = \dfrac{ Given \ wt.}{Molecular \ wt.}$

• Also ,

$\sf\longrightarrow n = \dfrac{ Number \ of \ particles }{Avogrado's\ Number}$

• From above two ,

$\sf\longrightarrow \red{ \dfrac{ Number \ of \ particles }{Avogrado's\ Number} = \dfrac{ Given \ wt.}{Molecular \ wt.}}$

• So that ,

$\sf\longrightarrow \dfrac{ Weight}{ 32g}= \dfrac{ 2.01 * 10^{24}}{6.022 * 10^{23}} \\\\\\\sf\longrightarrow \dfrac{ Weight}{ 32g}= \dfrac{10}{3} \\\\\\\sf\longrightarrow Weight = \dfrac{10}{3}* 32g \\\\\\\sf\longrightarrow \boxed{\pink{\frak{ Weight_{(Sulphur)}= 106.66 \ grams }}}$

Hence the mass in grams of Sulphur is 106.66 g .