Calculate the mass in grams of an impurity of molar mass 100 g/mol which would be required to raise the boiling point of 50g of chloroform by 0.30K (Kb for chloroform=3.63 K kg/mol)
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Given weight = 24 g
Molecular weight = 32 g
24
No. of moles (n) = 32 = 0.75 mol As we know that work done in an
isothermal process is given as
P₁
P
2
W = -2.303nRT log
Given:
T = 298 K
P₁ = 1.6 × 105 Pa = 160 kPa
P2 = 100 kPa
Therefore,
160
W = -2.303 x 0.75 x 0.0821 × 298 × log → W = -42.26 x log 1.6 = -8.62 atm - L
100
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