Question

Calculate the mass (in metric tons) of a blade made of aluminum, m_{blade}^{al}m blade al , setting the stress limit equal to fatigue limit of the material, \sigma_0^{al}

Answer 1

Here is your answer:

Explanation:

First calculate this

A _0 ^flap =  81 *8π *σ_0^ flap *h _0^ flap *ρair *V  *r ^2 *L  ^3

σ_0^ flap=150*10^6

then calculate

A _0 ^edge and σ_0^edge=150*10^6

then

M=2*(A _0 ^flap+A _0 ^edge)*86*2700

 finally

M/1000 we need in tons

Answer 2

Given:

m_{blade}^{al}m blade al , setting the stress limit equal to fatigue limit of the material, \sigma_0^{al}

To Find:

Mass (in metric tons) of  blade made of aluminum

Solution:

M blade (Al) = Ao×l×rho_AL

Ao AL=[(2×A flaps)+(2×A edge)]

A edge=[(Rho mat×g×L^2)/(St edge×ho edge-rho mat×g×)]×Aflaps

Assuming the basic conditions

g=10 $ms^{-2}$

Optmal wind speed = 11 $m/s$

Rho_air= 1.2

A edge = 0.048  

A flaps =0.096

Ao=[(2×0.096 )+(2×0.048 )= 0.288

M blade (Al) = Ao×l×rho_AL = [(0.288 )×(87 )×(2700 )]

M blade (Al) = 67651.2 = 67.65 tons