calculate the mass of 0.5 mole of sugar (c12h22o11)
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Answered by
237
mass of C = 12u mass of H = 1u mass of O = 16u
amu of sugar =( 12*12) + (1*22)+ (16*11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles * molar mass = 0.5 * 342 = 171 gram
amu of sugar =( 12*12) + (1*22)+ (16*11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles * molar mass = 0.5 * 342 = 171 gram
Answered by
71
mass/molar mass = number
of moles
number of moles x molar mass = mass
molar mass of sugar = 342.29 g/mol
mass = 0.5 x 342.29 = 171.145 g
number of moles x molar mass = mass
molar mass of sugar = 342.29 g/mol
mass = 0.5 x 342.29 = 171.145 g
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