Question

Calculate the mass of 0.5 mole of sulphuric acid (H2SO4). (Given atomic mass of H = 1 u, C = 12 u, O = 16 u, Na = 23u, S = 32 u, Ca = 40u)

Answer 1

Explanation:

Molar mass of sulphuric acid = 2+ 32 + 64

= 98 g/mol

mass of 0.5 mole = 98÷2

= 49g/mole

hope it helps

Answer 2

Answer:

The mass of 0.5 mol of $H_{2}SO_{4}$ is 49g.

Explanation:

In order to find out the mass of 0.5mol of $H_{2}SO_{4}$, we will using the following formula-

$Mole=\frac{Mass}{Atomic Mass}$

The atomic mass of $H_{2}SO_{4}$ can be calculated as follows:

• We have the atomic mass of each element.

1. H- 1u × 2
2. O- 16u × 4
3. S- 32u × 1

⇒ 2 + 64 + 32

⇒ 98u

Now we can find the mass of $H_{2}SO_{4}$.

$0.5= \frac{Mass}{98}$

$0.5*98=Mass$

$Mass= 49g$ of $H_{2}SO_{4}$