Calculate the mass of 1.0505 × 10^23 molecules of carbon dioxide ?
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Answered by
2
mass = 1.0505*10power23/6.022*10power23*44
since CO2mass = 44u
=> mass = 7.67grams
since CO2mass = 44u
=> mass = 7.67grams
Answered by
9
mass = 1.0505*10power23/6.022*10power23*44
since CO2mass = 44u
=> mass = 7.67grams
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