Question

calculate the mass of 1.204*10^23 atoms of Nitrogen ​

Answer 1

Answer:

Explanation:

M = N₂= 14 ×2= 28

N= 1.204 ×10²³

N₀= 6.022 × 10²³

N/N₀=m/M

m=N/N₀    ×      M

=1.204  × 10²³/ 6.022 × 10²³ .  ×  28

=5.6 g

Answer 2

Answer:

2.5 gram.

Explanation:

One mole of any element contains Avogadro's number of atoms, that is 6.02x10^23 atoms. Technically you divide the mass by the molar mass and then multiply by Avogadro's number. 14 grams is the molar mass of nitrogen meaning that one mole of nitrogen atoms is 14 grams.