Question

calculate the mass of 1.2044×10^23 molecules of Oxygen​

Answer 1

first it is 12.044x10^23

number of mole of oxygen=given number of molecules /avogadro number

avogadro number=12.044x10^23

$number \: of \: mole \: of \: oxygen = \frac{12.044 \times 10 {}^{23} }{6.044 \times 10 {}^{23} }$

$mole \: of \: oxygen = 2$

$no \: ofmole \: = \frac{given \: mass}{molarmass}$

molar mass of oxygen is 16u

$2 mol= \frac{mass}{16u}$

$mass \: ofoxygen = 32gram$

Answer 2

Answer:

first it is 12.044x10^23

number of mole of oxygen=given number of molecules /avogadro number

avogadro number=12.044x10^23

number \: of \: mole \: of \: oxygen = \frac{12.044 \times 10 {}^{23} }{6.044 \times 10 {}^{23} }numberofmoleofoxygen=6.044×102312.044×1023

mole \: of \: oxygen = 2moleofoxygen=2

no \: ofmole \: = \frac{given \: mass}{molarmass}noofmole=molarmassgivenmass

molar mass of oxygen is 16u

2 mol= \frac{mass}{16u}2mol=16umass

mass \: ofoxygen = 32grammassofoxygen=32gram