Question

calculate the mass of 1 dm3 of NH3 gas at 30°c 1000mmhg pressure considering tha NH3 behave ideally​

Answer 1

calculate the mass of 1 dm3 of NH3 gas at 30°c 1000mmhg pressure considering tha NH3 behave ideally?

V1 = 302 ml

P1 = 0.52 atm

P2 = ?

V2 = 69 ml Boyle's Law P1V1 = P2V2

P2 = P1V1/V2 P2 =

(0.52 atm)(302 ml)/69 ml

P2 = 2.3 atm...

Answer 2

Answer:

0.907 grams

Explanation:

1)..PRESSURE OF GAS =P= 1000MM/HG=1000/760 TORR = 1.315 atm

2).. VOLUME OF GAS =V= 1dm3

3).. TEMPERATURE=t= 30C = 30+293.16K =303k

4).. MOLECULAR MASS OF GAS =17g/mol

5)..Mass of nh3 gas =m=?

SOLUTION....

ACCORDING TO GENERAL GAS EQUATION..

PV=M/m RT

REARRANGING...

m=PVM/RT

AS... (..R =0.0821 dm3 atm k/-1 mol-1 )

m=1.315(1)(18)/0.0821(303)

mass of nh3 =0.907grams