Question

Calculate the mass of 11.2 L of CO2 at STP​

Answer 1

Answer:

22g

Explanation:

According to avogrado's law 1 mole of gas has 22.4 L of volume at STP.

Since there is only 11.2 L ( half of 22.4) of CO2, its obvious that there is only half a mole(0.5 mole) .

Molar mass of co2 = 12 + 2(16)

= 12 + 32

= 44 g

1 mole of CO2 has 44g mass

0.5 mole of CO2 will have (44 x 0.5)g mass

Therefore, 11.2 L of CO2 at STP will have mass 22g.

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Answer 2

Explanation:

We have,

• Volume of CO2 = 11.2 liters

We know that for gases at STP,

no. of moles = 22.4/volume (liters)

= 22.4/11.2 = 2 moles

mass of 1 mole carbon dioxide = 44 g

mass of 2 moles of carbon dioxide = 44×2 = 88 g