Question

Calculate the mass of 12.044×10^24 particles of sodium carbonate ​

Answer 1

Answer:

Total mass of Na2CO3 = 2118 grams

Explanation:

Avogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.023 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction

Now as per question statement, we are given that we have 12.044×10^24 particles of sodium carbonate.

No of moles of Na2CO3 = 12.044×10^24 / 6.023 × 1023

No of moles of Na2CO3 = 20 moles

Molar mass of Na2CO3 = 105.9888 g/mol

Total mass of Na2CO3 = 20 x 105.9

Total mass of Na2CO3 = 2118 grams