Question

Calculate the mass of 12.044 × 10 ki power 23 number of nitrogen

Answer 1

Answer :-

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Mass of 6.022 × 10²³ number of Nitrogen is 14 g

Then ,

Mass of 12.044 × 10²³ number of Nitrogen is 2 × 14 g = 28 g.


•°• The required answer is 28g

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Thanks!

Answer 2

given no. of molecules = 12.044* 10²³
avogadro no = 6.022*10²³
no of moles = no of molecules / avogadro no
= 12.044 *10²³ /6.022* 10²³
= 2moles

molar mass of nitrogen = 14g
given mass = molar mass * no of moles
given mass = 14*2
given mass = 28

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