Chemistry, asked by gurpreetsingh6491, 1 year ago

Calculate the mass of 120 cc of nitrogen at NTP . How many numbere of mopecules are present in it?

Answers

Answered by Advik007
41

1cm3 = 1/1000000 m3

120 cm 3 = 120/1000000 m3


1 m3 = 1000 L

120/1000000 m3 = 120/1000 L


Moles = volume/22.4

Moles = 120/22400

Moles = 0.0053 mols


Number of atoms in 1 mole is 6.023 * 10^23

Number of atoms in 0.0053 moles ==

3.22 * 10^21


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