Calculate the mass of 120mL of N2 at 150oC and 750mm of Hg pressure. Given:
R=0.0821 L atm/K/mol, molar mass of N2=28 g/mol
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Answer:
0.095g
Explanation:
PV = nRT
(750÷760)atm x (120÷1000)l = (m÷28) x 0.0821atm L/mol/K x (150+273)K
0.98 x 0.12 = (m÷28) x 34.73
0.1176 = 1.24m
m = 0.095 g
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