Question

Calculate the mass of 18.066×1023 number of NH3 molecules. (Given atomic mass of nitrogen= 14 u and hydrogen=1 u) No spam only correct answers!​

Answer 1

Answer:

given mass(w) =?

molar mass (M)of NH3 is 14+1×3=17g

no. of molecules= 18.066×10^23

Formulae to be used = no. of particles =W/M× avogardo constant

and n =W/M

Explanation:

W/17×6.022×10^23=18.066×10^23

W=18.066×10^23×17/6.022×10^23

W= 17×3 g

W=51g

For better explanation plz check the image inserted below.

Answer 2

Answer:

Explanation:

Given:

Mass(w) =?

Molar mass (M)of NH3 is 14+1×3=17g

No. of molecules= 18.066×10^23

Formula to be used = no. of particles =W/M× Avogadro constant

And n =W/M

W/17×6.022×10^23=18.066×10^23

W=18.066×10^23×17/6.022×10^23

W= 17×3 g

W=51g