Question

Calculate the mass of 2.4 litres of oxygen gas at S.T.P.​

Answer 1

Heya!

Here is ur answer...

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As we know,

mass of oxygen, of 22.4 l = 16

Molecular Mass of O2 = 2(16) = 32g

Therefore,

32g of O2 gives 22.4 l at STP ----(1)

Let, x g of O2 gives 2.4 l at STP -----(2)

Now,

eq.(2)/(1)

$\frac{x}{32} = \frac{2.4}{22.4} \\ \\ 22.4 \: x = 32(2.4) \\ \\ x = \frac{76.8}{22.4} \\ \\ x = 3.24 \: g$

Hence, 3.2g of O2 gives 2.4l at STP

hope it helps

Answer 2

Answer:

3.42 g

Explanation:

Mass of 2.4 litres of oxygen gas at stp

as we know,

gm.mol.wt of oxygen gas = 2 *16=32g

Therefore, 32g of O2 will occupy 22.4 l

So.? g of O2 will occupy 2.4 l

By unitary method,

32g ->22.4 l

? g->2.4l

g-> 2.4*32/22.4 =3.42 g