Question

calculate the mass of 2.5 mole of CaCO3

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Mass\:of\:CaCO_3\:is\:250g }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mole (n) = 2.5

• Molecular weight of $\sf{CaCO_3}$

$\large\implies{\sf M_w= 40+12+(3×16)}$

$\large\implies{\sf M_w=100}$

$\large\underline\pink{\sf To\:Find: }$

• Mass of $\sf{CaCO_3}$= ?

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We know ,

$\large{\boxed{\sf Mole(n)=\frac{Mass(m)}{Molecular\:Mass(M_w)} }}$

$\large\implies{\sf 2.5=\frac{m}{100} }$

$\large\implies{\sf m=2.5×100}$

$\large\implies{\sf m=250g}$

$\red{\boxed{\sf Mass\:of\:CaCO_3\:is\:250g }}$

Answer 2

The mass of given amount of calcium carbonate is 250 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Moles of calcium carbonate = 2.5 moles

Molar mass of calcium carbonate = 100 g/mol

Putting values in above equation, we get:

$2.5mol=\frac{\text{Mass of calcium carbonate}}{100g/mol}\\\\\text{Mass of calcium carbonate}=(2.5mol\times 100g/mol)=250g$

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