Question

Calculate the mass of 3.011*10^23 atoms of nitrogen.

Answer 1

Answer:

the mass is 7g

Explanation:

$3.011 \times 10 {}^{23} \: atoms$

$= 3.011 \times 10 {}^{23} atoms \: = \frac{3.011 \times 10 {}^{23} atoms}{6.022 \times 10 {}^{23} atoms}$

$= 3.011 \times 10 {}^{23} atoms \: = \frac{3.011 \times 10 {}^{23} atoms}{6.022 \times 10 {}^{23} atoms}$= 1/2 mole = 0.5 mole

First we apply the formula:

$no. of \: moles \: = \frac{mass \: of \:n }{molar \: mass \: of \: n}$

= Mass of N atoms = No. of miles × Molar mass of N

= Mass of N atoms = 0.5 mole × (atomic mass of nitrogen)

= Mass of N atoms = 0.5 ×14

= Mass of N atoms = 7g

Therefore, the mass of 3.011 × 10^23 number of N atoms is 7g