Question

calculate the mass of 3.011*10^23 of capital N atoms (atomic mass is 14u)

Answer 1

to calculate the mass of 3.11*10^24 atoms of nitrogen:-
we know that 6.022*10^23 atoms of nitrogen = 1 mole of carbon atoms
1 mole of nitrogen atoms = 14 gram
6.022*10^23 nitrogen atoms weigh = 14 gram
3.011*10^23 atoms of carbon weigh = 7 gram
mass of 3.011*10^23 atoms of carbon is 7 gram.

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Answer 2

Given no: of particles = 3.011 × 10²³

No : of moles = Given no: of particles ÷ Avogadro no:
= 3.011× 10²³ ÷ 6.022× 10²³
= 0.5 moles

Molar mass of Nitrogen ( N) = 14 grams

No: of moles = Given mass ÷ Molar mass

∴ Mass = Molar mass × No: of moles
= 14 × 0.5
= 7 grams
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