Question

calculate the mass of 3.011*10^24 molecules of nitrogen gas.

Answer 1

Fix* It's 6.022x10²³ particles

Mass of 1 mol N2 = 28g

Hope this helps.

Answer 2

The mass of 3.011 × 10²⁴ molecules of Nitrogen gas is equal to 140 grams.

Given:

The number of molecules of Nitrogen gas = 3.011 × 10²⁴

To Find:

The mass of Nitrogen Gas present.

Solution:

→ According to the mole concept, the mass of 6.022 × 10²³ molecules of any gas is equal to the molar mass of the gas.

∴ The mass of 6.022 × 10²³ molecules of Nitrogen gas = 28 grams

$\boldsymbol{\therefore Mass\:of\:3.011\times10^{24}\:molecules\:of\:Nitrogen=\frac{28}{6.022\times10^{23} } \times 3.011\times10^{24} }\\\\\boldsymbol{\therefore Mass\:of\:3.011\times10^{24}\:molecules\:of\:Nitrogen=140\:grams}$

Therefore the mass of 3.011 × 10²⁴ molecules of Nitrogen gas comes out to be equal to 140 grams.

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