Chemistry, asked by lkkaundal2005, 7 months ago

calculate the mass of 3.011×10^24 molecules of water​

Answers

Answered by PoojaBurra
15

Given:

Number of water molecules = 3.011×10²⁴

To find:

The mass of the water molecules

Calculation:

1 mole of a compound contains 6.023×10²³ molecules

=> Mass of 6.023×10²³ molecules = Molecular mass of H₂O

=> Mass of 6.023×10²³ molecules = 2(1) + 16 = 18g

=> Mass of one molecule = 18 / 6.023×10²³ grams

=> Mass of 3.011×10²⁴ molecules = (18 / 6.023×10²³) × 3.011×10²⁴

                                                      ≈ 90 grams

The mass of 3.011×10²⁴ molecules of water is 90 grams

Answered by chandelpallavi673
1

Answer:

3.011*10²⁴ molecules has 90 gram of mass

Explanation:

Molecular formula of H2O=2+16=18u

Mass of 1 molecule of water=18/6.022*10²³

As we know that,

1 mole =6.022*10²³

So, mass of 3.011*10²⁴ molecules of water=18*3.011*10²⁴/6.022*10²³

=3*3.011*10

=9.0*10

=90

So, 3.011*10²⁴ has 90 gram of mass.

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