Question

calculate the mass of 3.011×10²³ molecules of CA(OH)² with full explanation​

Answer 1

Answer:

37g

Explanation:

number of moles = 3.011x10²³/6.022x10²³ = 0.5

Now,

molar mass of Ca(OH)2 = 1x40+2x16+2x1

= 40+32+2 = 74g

1 mole = 74g, then

0.5 mole = 0.5x74g = 37g.

Answer 2

Answer:

one moles contains 6.023×10^23 molecules

so, 0.5moles contains 3.011×1023 molecules

no of moles=wt /gmw ;gmw of ca(oh) 2= 74g

0.5 = wt/74

wt = 37

therefore mass of ca(oh) 2 in 3.011×10^23 molecules is 37 grams