Question

calculate the mass of 3.01x10^23 atoms of sulphur.​

Answer 1

Answer:

Hey mate

Here's ur answer.....

no.of moles= no.of atoms/avagadro's no

= 3.01×10^23/6.022×10^23

=0.51 mol

no. of moles=given mass /molecular mss

0.51=x/32

given mass=16.32.

mass of sulphur =16.32 g

Hope it helps.

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Answer 2

Mass of $3.01\times 10^{23}$ atoms of sulphur weigh 16.0 grams.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text{Avogadro's number}}=\frac{3.01\times 10^{23}}{6.023\times 10^{23}}=0.500moles$

1 mole of sulphur weighs = 32.065 g

0.500 moles of sulphur weigh = $\frac{32.065}{1}\times 0.500=16.0g$

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