Question

calculate the mass of 44.8 L Nh3 kept at stp

a) molecular mass of Nh3 17
b) how many molecular of Nh3 are present in it​

Answer 1

Answer:

P is pressure (1 under STP), V is the volume in liters, n is the number of moles, R is the gas constant (0.082) and T the temperature in Kelvins (273 under STP). So, rearrange for n and solve and you get:

n=PV/RT = 1*44.8/(0.082*273) = 2 moles.

Ammonia is NH3 so the molecular weight is 17 g/mole. To get the mass, multiple the # moles times the molecular weight:

2 moles * 17 grams/mole = 34 grams