Question

calculate the mass of 50 cm3 of CO2 at stp ​

Answer 1

Answer:

Explanation:

Molar mass of CO = 12 + 16 = 28 g/mol. Therefore, 22.4 L ( 22400 cm3) is the volume of 28g CO at STP. 56 cm3 will be the volume of (28/22400) x 56 = 0.07 g of CO at STP

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Answer 2

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Answer:

0.0625 g

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Explanation:

[1 mole = 1 g mol. wt. and occupies 22.4 lit. at STP]

g mol. wt. of carbon monoxide = 12 + 16 = 28 g.

28 g of CO occupies 22400 cc at STP.

How many grams of CO will occupy 50 cc at STP= 28x50/22400= 0.0625g.

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