calculate the mass of 6.022*10^24 molecules of nitrogen when molar mass of nitrogen is 28g/ mole
Answers
Answered by
3
no. of moles =6.022*10^24/Na =10moles
mass = 10*28=280g
mass = 10*28=280g
Answered by
6
1 mole of Nitrogen contains = 6.022 x 10^23 molecules = 28gm
Total moles =
(6.022 x 10^24)/(6.022 x 10^23)
= 10 moles
Mass of 1 mole = 28gm
Mass of 10 moles = 28 x 10 = 280 gm
Total moles =
(6.022 x 10^24)/(6.022 x 10^23)
= 10 moles
Mass of 1 mole = 28gm
Mass of 10 moles = 28 x 10 = 280 gm
Ayushpratapsingh2210:
see in ur question.
Similar questions