Question

calculate the mass of 6.022×10 atoms of potassium

Answer 1

Answer:

Explanation:

Solution —

Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g

No. of moles of CaCO3

= No. of molecules/Avogadro constant

= 6.022 × 1023/ 6.022 × 1023

= 1 mole

Mass of CaCO3

= No. of moles × molar mass

= 1 × 100 g = 100 g.