Question

Calculate the mass of 6.022×1023 molecular units of NH4Cl.

Answer 1

Answer:

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Answer 2

Given : The compound is $NH_{4}Cl$

To find : The mass of $6.022*10^{23}$

Answer : we know that ,

number of moles = number of molecule ÷ avogadro number

= $\frac{6.022*10^{23} }{6.022*10^{23} } = 1$

Therefore , The mass of 1 mole of $NH_{4} Cl = 1 *$ molar mass

$=$ mass of 1 mole of $NH_{4} Cl$ = 53.5 g

Hence , the mass of $6.022*10^{23}$ molecular units of $NH_{4}Cl$ is 53.5g