Chemistry, asked by arun322, 1 year ago

Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3)

Answers

Answered by gagansharma53
12
please Mark it brainliest answer please
6.022∗1023 molecules are equal to 1Mole

1Mole of CaCO_{3}CaCO3​ has mass of 100g (mass of Calcium + mass of Carbon + 3 times the mass of Oxygen)

Therefore, 6.022*10^{23}6.022∗1023 molecules of CaCO_{3}CaCO3​has mass 100g
Answered by Anonymous
12
✨Molar mass of CaCO3 = 40+12+3×16 = 100 g


✨No. of moles of CaCO3


➡ No. of molecules/Avogadro constant

➡ 6.022 × 1023/ 6.022 × 1023

➡1 mole

Mass of CaCO3

=➡No. of moles × molar mass

➡ 1 × 100 g = 100 g.
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