Question

calculate the mass of 6.022× 1023molecule of calcium carbonate class 9th
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Answer 1

Answer:

Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3). Solution —Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 gNo. ... of atoms/Avogadro constant= 12.044 × 1023/6.022 × 1023= 2 moleMass of carbon atoms= No. of moles × atomic mass= 2 × 12= 24 g.