Question

Calculate the mass of 6.022multiply by 10^22 atoms of He​

Answer 1

• Avogadro's constant says that 1 mole of any atom contains 6.022⋅1023 atoms. In this case you have 3.40⋅1022 atoms: 3.40⋅1022atoms 6.022⋅1023atoms mol = 5.65⋅10−2mol.
• The atomic mass of helium (He) will give you the weight of one mole of this molecule: 1 mol = 4.00 gram: 4.00gmol ⋅5.65⋅10−2mol = 0.226g.