Question

calculate the mass of 6.022x10^23 atoms of silver

Answer 1

Answer:

ⒽⒺⓇⒺ ⒾⓈ ⓎⓄⓊⓇ ⒶⓃⓈⓌⒺⓇ ⒻⒺⓁⓁⓄⓌ ⒸⓁⒶⓈⓈⓂⒶⓉⒺⓈ

Explanation:

Gram atomic mass of silver =108g

Since -108g of Ag is equal to 1 mole of Ag

therefore 6.023×10

23

atoms of Ag are contained

by = 108 g of Ag

6.023×10

23

atoms will be contained by

6.023×10

23

108

×6.023×10

23

=0.108g