Question

Calculate the mass of 6.022x10^23 molecule of Calcium Carbonate(CaCo3)

Answer 1

Explanation:

Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. ... of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No. of moles × molar mass = 1 × 100 g = 100 g.