Calculate the mass of a body whose volume is 2 m^3 and relative density is 0.52.
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Answered by
20
Heya user ,
Here is your answer !!
We know that , Density ( D ) = Mass ( M ) / Volume ( V ) .
=> M = D × V .
Given , V = 2 m³
and , R.D. = 0.52
so , density = 0.52 * 1000 kg/m³ = 520 kg/m³
So , mass ( M ) = 2 m³× 520 kg/m³ = 1040 kg .
Hope it helps !!
Here is your answer !!
We know that , Density ( D ) = Mass ( M ) / Volume ( V ) .
=> M = D × V .
Given , V = 2 m³
and , R.D. = 0.52
so , density = 0.52 * 1000 kg/m³ = 520 kg/m³
So , mass ( M ) = 2 m³× 520 kg/m³ = 1040 kg .
Hope it helps !!
TPS:
you didn't find density.
Answered by
5
Volume of the body = 2 m^3
Relative density, RD = 0.52
Mass of body = Density × volume.
We know volume and relative density. We need to find density first.
Density of body = RD × density of water
=> density = 0.52 × 1000 = 520 kg/m^3
Now, mass of body = density × volume
=> Mass = 520 × 2 = 1040 kg
Hence mass of body is 1040 kg.
Relative density, RD = 0.52
Mass of body = Density × volume.
We know volume and relative density. We need to find density first.
Density of body = RD × density of water
=> density = 0.52 × 1000 = 520 kg/m^3
Now, mass of body = density × volume
=> Mass = 520 × 2 = 1040 kg
Hence mass of body is 1040 kg.
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