Question

calculate the mass of a body whose volume is 2m3 and r.d is 0.52

Answer 1

Answer:

R.D. of silver = 0.52. Volume = 2 m3. Density of body in S.I. = 0.52 × 103 kgm3. ∴ Mass = Density × volume = (0.52 × 103) × 2 = 1040 kg .

Answer 2

Given,

The volume of a body = 2 m^3

Relative density of the body = 0.52

To find,

The mass of the body.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Relative density of a body = density of the body/density of water

=> Density of the body = (relative density of a body)(density of water)

{Equation-1}

Also, density = mass/volume

=> mass = density × volume

{Equation-2}

The density of water = 1000 Kg/m^3

Now, according to equation-1;

The density of the given body

= (relative density of a body)(density of water)

= 0.52 × 1000 Kg/m^3

= 520 Kg/m^3

Now, according to the equation-2;

The mass of the body

= density of the body × volume of the body

= 520 Kg/m^3 × 2 m^3

= 1040 Kg

Hence, the mass of the body is equal to 1040 Kg.