Calculate the mass of a non-volatile solute (molar mass 40 g mol-1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%
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Let p be the vapour pressure of pure octane. The vapour pressure of solution will be
100 /80 p =0.8 p
Molar mass of solute (M) and octane (m) are 40 g/mol and 114 g/mol respectively. Mass of octane, w is 114 g.
(p-p')/p = W x114 / 40 x 114
W = 8g
Thus, 8g of solute is required
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