Question

Calculate the mass of aluminium present in 34g of aluminium oxide, Al2O3 (Atomic mass is 27).​

Answer 1

Answer: (204 g)/(101.96 g/mol) = 2.001 mol. 2(2.001) = 4.002 moles of aluminium in the sample. Then there are (4.002 mol)(26.98 g/mol) = 107.97 g of Al.01

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Answer 2

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$(204 g)/(101.96 g/mol) = 2.001 mol.$

$2(2.001) = 4.002 \: moles \: of \: aluminium \ \\ : in \: the \: sample.$

$Then \: there \: are (4.002 mol)(26.98 g/mol)$

$= 107.97 g of Al.$