Question

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium.

Answer 1

♣️Question:

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium.

♣️Answer:

✔Formula used:

$\large{ \sf{ \bullet{ \boxed{ \bold{no. \: of \: moles = \frac{mass \: in \: grams}{atomic \: mass}}}}}} \\ \sf{ \red{ \underline{ \underline{ \dag{ \: for \: element}}}}} \\ \\ \large{ \bullet{ \boxed{ \sf{ \bold{1 \: mole = 6.022 \times {10}^{23} atoms}}}}}$

♣️Solution:

➕No. of moles of cadmium:

$\large{ \sf{ = \frac{6.35g}{112.4u} }} \\ \\ \large{ \sf{ = 0.056moles}}$

➕No. of atoms of Cadmium:

$\large{ \sf{ = 0.056 \times 6.022 \times {10}^{23} }}$

✔To find: Mass of Al having same no. of atoms

➕We know....

$\large{ \sf{ \to no. \: of \: atoms = moles \times 6.022 \times {10}^{23} }} \\ \large{ \sf{ \to{no. \: of \: atoms = \frac{mass \: in \: gms}{atomic \: mass} \times 6.022 \times {10}^{23} }}}$

$\large{ \sf{ \to \: \: 0.056 \times \cancel{6.022 \times 10 {}^{23} } = \frac{mass \: of \: aluminium}{27} \times \cancel{6.022 \times 10 {}^{23} }}} \\ \\ \large{ \sf{ \to \: 0.056 = \frac{mass \:in \:gms}{27} }} \\ \\ \large{ \sf{ \to \: mass \: in \:gms= 0.056 \times 27}} \\ \large{ \sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \red{ = 1.52 \: gms(approx)}}}}$

♣️So final answer:

$\huge{ \boxed{ \bold{ \green{ = 1.52 \: gms}}}}$

Answer 2

Answer:

1.52gms

Explanation: