Calculate the mass of Ammonia present in 1.5 x 10^ 23 molecules
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Answered by
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Mass of 1 mole of NH3 molecule = 17 g.
So 6.023 x 1023 molecules = 17g
∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g
So 6.023 x 1023 molecules = 17g
∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g
Answered by
1
Answer:
Hey mate,
Your answer is as follows:
Mass of 1 mole of NH3 molecule = 17 g.
So 6.023 x 1023 molecules = 17g
∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g
Explanation:
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