Chemistry, asked by kariyapriti315, 7 months ago

Calculate the mass of Ammonia present in 1.5 x 10^ 23 molecules

Answers

Answered by 58Xbkhyaatisuman
2
Mass of 1 mole of NH3 molecule = 17 g.

So 6.023 x 1023 molecules = 17g

∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g
Answered by ElegantMermaid
1

Answer:

Hey mate,

Your answer is as follows:

Mass of 1 mole of NH3 molecule = 17 g.

So 6.023 x 1023 molecules = 17g

∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g

Explanation:

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