Question

calculate the mass of ammonia when 42g nitrogen gas reacts with 6g hydrogen​

Answer 1

Answer:

Hydrogen and nitrogen react to form Ammonia (NH3). ... Now, according to the stoichiometric equation, 6g of H2 produces 34g of NH3. So, 1.09g of H2 will produce = (1.09 × 34)/6 = 6.176g of NH3.

Explanation:

The stoichiometric equation is:

3H2 + N2 → 2NH3

According to the stoichiometric equation, 6g of H2 combines with 28g of N2.

So, 1.09g of H2 will combine with = (1.09 × 28)/6 = 5.0866g of N2.

Now, 14 of N2 is used, according to the question.

So, H2 is the limiting reagent and N2 is the excess reagent.

Now, according to the stoichiometric equation, 6g of H2 produces 34g of NH3.

So, 1.09g of H2 will produce = (1.09 × 34)/6 = 6.176g of NH3.

Answer 2

Answer:

N2+3H2->2NH3

using this stoichiometric equation

H2 is the limiting agent so only 28 g ammonia reacts with 6g H2

in the same way 42 g ammonia will produce no more than 34 g ammonia(authentic)