calculate the mass of ammonium sulfate that can be made from 51 grams of ammonia. 2NH₃ + H₂SO₄ → (NH₄)₂SO₄ (keeping the mole concept in mind) ( people please if you don't know the answer or didn't understand the question.... DON'T SPAM just to earn false point.)
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Answered by
5
Answer:
198g of (NH4)2SO4
Explanation:
2 mole NH3 -> 1 mole (NH4)2SO4
1 mole NH3 -> 1/2 mole (NH4)2SO4
17g NH3 -> 66g (NH4)2SO4
1g NH3 -> 66/17 g (NH4)2SO4
51g NH3 -> 51 x 66/17 g (NH4)2SO4
= 198g (NH4)2SO4
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Answered by
2
Answer:
7962 grams
Assuming that there is an excess in ammonia, there are 7962 grams of of ammonium sulfate that can be produced for every 60 moles of sulfuric acid that reacts.
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