Question

Calculate the mass of Anhydrous sodium Carbonate require bfor the preparation of 250cm of molar solutions

Answer 1

Molar mass of sodium carbonate = 23x2 + 12 + 16x3 = 106 g

Molarity of the required solution = 0.1 M (decimolar)

Mass of Na2CO3 required to make 1 litre (1000 cm^3) of the solution = molarity x molar mass = 0.1x106 = 10.6 g

So, mass of Na2CO3 required for 200cm^3 = (10.6x200)/1000 = 10.6/5 = 2.12 g (answer)