Calculate the mass of anhydrous sodium carbonate required for the preparation of 250 cm ^3 of 0.05 Mol per dm^3
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Answer:
This question is asking about how much of a compound (in terms of mass) we need to dissolve to make a solution of a given concentration.
Recall,
M
=
mol
L
Given,
V
=
0.250
L
[
N
a
2
C
O
3
]
=
0.0500
M
Hence,
mol
=
L
⋅
M
=
1.25
⋅
10
−
2
mol
⋅
106
g
N
a
2
C
O
3
≈
1.33
g
of sodium carbonate are needed to make the solution requested.
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