calculate the mass of aron in 10kg of Fe2O3 RAM is 56 of Fe.
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Explanation:
Ferric oxide = iron(III) oxide = Fe2O3
molar mass Fe2O3 = 159.69 g/mol
molar mass Fe = 55.845 g/mol
10 kg × 0.8 Fe2O3 = 80 kg Fe2O3
80 kg Fe2O3 × (1 mol Fe2O3/159.69 g Fe2O3) × (2 mol Fe/1 mol Fe2O3) × (55.845 g Fe/1 mol Fe) = 55.953 kg
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