calculate the mass of body whose volume is 2m^3 and relative density is 0.52
Answers
Answered by
9
relative density
=density of the body(d) / density of water
0.52 = d/1000kg /m^3
d = 0.52 × 1000
d = 520 kg/ m^3
mass = density(d) × volume
mass = 520 kg/ m^3 × 2m^3
mass = 1040 kg
therefore ,mass of body= 1040 kg
______________________________
Your Answer : Mass= 1040kg
______________________________
=density of the body(d) / density of water
0.52 = d/1000kg /m^3
d = 0.52 × 1000
d = 520 kg/ m^3
mass = density(d) × volume
mass = 520 kg/ m^3 × 2m^3
mass = 1040 kg
therefore ,mass of body= 1040 kg
______________________________
Your Answer : Mass= 1040kg
______________________________
tanishkasri:
thank you so much
Answered by
1
Answer:
Hope this helped you.
Thank you.
Attachments:
Similar questions
Physics,
7 months ago
English,
7 months ago
Math,
7 months ago
Computer Science,
1 year ago
Science,
1 year ago
Social Sciences,
1 year ago
History,
1 year ago