calculate the mass of cacl2 formed when 5 moles of chlorine reacts with calcium metal?
Answers
Answered by
14
Answer:
554.9 g
Explanation:
1 mole of chlorine give 1 mole of CaCl2
=> 5 mol of Cl2 will give 5 mol of CaCl2
=> mass of CaCl2 = moles * molar mass = 5 mol * 110.98 g/mol = 554.9 g
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Answered by
5
Answer:
Explanation:
5×110.98=554.9 g
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