Question

calculate the mass of CaCO2 required to react completely with 25 ml of 0.75 M HCL,calculate volume of CO2 released at STP in this reaction​

Answer 1

Answer:

The1000mL of HCl=27.375g then the 1 ml of solution contains HCl

1000×1

27.375

25ml of solution which contains HCl=

1000×25

27.375

=0.684g

The chemical equation can be given as:

CaCO

3(s)

+2HCl→CaCl

2

+CO

2

+H

2

O

2mol of HCl reacts with 1 mol of CaCO

3

The amont of CaCO

3

reacted is given by,

71

100

×0.684g=0.9639g≈0.94g