Calculate the mass of calcium ions present in 1L of hard water if the concentration of calcium ions is 40 ppm. (Assume
density of hard water to be 1g/cc)
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The density of water sample is 1.0 g/ml.
Thus, 1 L (or 1000 mL) of water sample weighs 1 kg (or 1000 g).
486 ppm corresponds to 486 g of calcium bicarbonate in 1000 g or 1000 L of water sample.
Thus, 1 L of water sample contains 0.486 g of calcium bicarbonate.
The molar mass of calcium bicarbonate is 162.11 g/mol.
The molarity of the solution =
Molar mass of calcium bicarbonate×Volume of water sample
Mass of calcium bicarbonate
=
162.11×1
0.486
=3.0×10
−3
M
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