calculate the mass of calcium oxide required that reacts with 852g of P4 O10.
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Explanation:
So, 18 moles of CaO reacts with 3 moles of P₄O₁₀ to give 6 moles of Ca₃(PO₄)₂. Therefore 1008 grams of CaO is required to react with 852 grams of P₄O₁₀.
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